Euler Problem 65: Find the sum of digits in the numerator of the 100thconvergent of the continued fraction for e.
Sa mathmematica došao do sljedećeg:
an = ContinuedFraction[E, 101][[100]]; For[i = 99, i > 0, i--, an = ContinuedFraction[E, 101][[i]] + 1/an ]; Total[IntegerDigits[Numerator[an]]]
Ili:
Total[IntegerDigits[ Numerator[FromContinuedFraction[ContinuedFraction[E, 100]]]]]
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